(3b^2+3b-7)/(b-2)

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Solution for (3b^2+3b-7)/(b-2) equation:


D( b )

b-2 = 0

b-2 = 0

b-2 = 0

b-2 = 0 // + 2

b = 2

b in (-oo:2) U (2:+oo)

(3*b^2+3*b-7)/(b-2) = 0

3*b^2+3*b-7 = 0

3*b^2+3*b-7 = 0

DELTA = 3^2-(-7*3*4)

DELTA = 93

DELTA > 0

b = (93^(1/2)-3)/(2*3) or b = (-93^(1/2)-3)/(2*3)

b = (93^(1/2)-3)/6 or b = (-(93^(1/2)+3))/6

(b+(93^(1/2)+3)/6)*(b-((93^(1/2)-3)/6)) = 0

((b+(93^(1/2)+3)/6)*(b-((93^(1/2)-3)/6)))/(b-2) = 0

( b+(93^(1/2)+3)/6 )

b+(93^(1/2)+3)/6 = 0 // - (93^(1/2)+3)/6

b = -((93^(1/2)+3)/6)

( b-((93^(1/2)-3)/6) )

b-((93^(1/2)-3)/6) = 0 // + (93^(1/2)-3)/6

b = (93^(1/2)-3)/6

b in { -((93^(1/2)+3)/6), (93^(1/2)-3)/6 }

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